Mechanical engineering forumlas.

[Brett Nortje]

This is to introduce high school students to the rigours of engineering, to let them see what the real world of engineering is about. If they are interested in engineering, or just sampling different fields, this is written just for them!

Let's start with "Torque required to raise load?"

This would be where the energy required to raise a load is based on the ability of the machine to perform by combustion to do the things required, because of the load, like a car frame that is supposed to go forwards - how much energy is required to make it move? How much energy per meter, or, more conventionally or usually, how much energy is needed to move for each kilometre?

The formula;

Let's skip to the brackets on the left? This would be where pie divided by pie equals one, [u] divided by [u] equals one, [d] and [m] divided by [d],[m] and [l] equals [m] and [l] so the answer for the brackets is three [4].

Then [d * 1.5] because [1F2D / 2] because the [m] is to the power of [d] equals [1d] * [1m] into the same thing in [d] equals [2d], yes? So the answer here is [1.5].

Multiplying [1.5] by [4] equals [6] or six, so the answer is to raise the torque by six times the load - there is six times as much energy required as mass to 'carry the load,' of course.

[Brett Nortje]

This will be where the engine compresses the combustion of the engine. This is where the steam released by the engine will push the gears of the engine to produce propulsion, of course. If we were to observe that the engine needs to compress the steam to push it through at 'high charge,' then it would stand to reason that the compression needs to be observed through this formula;

So, we could say that the compression ratio is equal to [v] to the power of [c] divided by [v] to the power of [c], which is [one], plus [22 / 7 / 4] six and a half divided by seven equals [0.73], is the same as [4 * 7 * 22] = [456 / 1000] as there were two multipliers, leaves [0.46].

Then, [0.4] * [8x] + [1] = [4.2]. So, the answer for compression ratios it to use 4,2.

[Brett Nortje]

This formula is about finding the limits of friction allowed onto a belt by the energy it gives off;

So, we would take the 'middle block' of the divided side, and find that everything divided by each other equals one, or, [1k] divided by [1u] because everything else divided by itself is one, yes? Then, we find that [k] minus [k] equals 0, so the answer is [u] times the power number? [n] - [0] = [n], so the number is 'prime.'

To find the prime number, we need to use [u^r] log [n]. so we would find the logarithm of the [u^r], which would be based on a prime number, so, [n] has a square root, [1], the answer is three!

This means the belt's friction wear limits is three times the load on it regarding the surface with the mass, so, in my terms, the 'density' or mass of the belt needs to be three times the energy exerted by the movement or momentum.

[Brett Nortje]

This is used for calculating how well the motion of the engine is in sync with the rest of the car and the workings of the engine for the stability of acceleration. In college you will find this will make or a few questions on your exam, nearly guaranteed, as it is essential for finding the way the engine works regarding 'getting a nice hum out of it for as long as possible.'

So [acceleration] to the power of [time] is supposed to be; - [1 A {meter}] * [24pie] * [4f {speed}] * [2] * ([velocity or momentum] * [time] - [phase in angles]). This means we need only take [speed] * [time] * [revolutions of 360] / [meters] to find how long it will travel soundly for.

[Brett Nortje]

This is where you want to bring electricity into the machine. This is best done by calculating the amount of energy needed to, first, turn the device or lift or whatever you want to do. Basically, electrical engineering works on volts to perform the movement of the device, where the device moves because the electricity is giving off magnetic waves to move. The electricity merely powers the circuits, it is the magnetism of electromagnetism that moves things. This is similar to drawing mass from food to fill your stomach, where your stomach's mass, the waves of magnetism, the physical force, the strong force, as the weak force is electrons, and, therefore, as the fundamental forces of the universe are electromagnetism and friction, means that the mass is effected, while the friction is affected by electricity.

So, if we were to observe that it is that way, then we could safely say that fires start by lone electrons freely roaming, and, gravity is where free protons roam, except that free roaming protons will result in coldness, as evidenced in my air conditioning devices. This means, at a state of balance, the gravity takes over from the protons, being dominant, as mass needs to be more than energy and friction to have the item not 'boil,' then we have gravity.

[Brett Nortje]

This is a formula for finding the amount of time the engine will continue for, most of the time. You will be asked this in your exams. Basically, it is about how much energy is required to keep the engine going for how long, of course, with conserving the 'acceleration.' This is like planting your foot on the accelerator lightly and finding it hum forwards, of course.

{\displaystyle _{\scriptstyle S}}{\displaystyle (\rho \mathbf {u} \cdot d\mathbf {S} )\mathbf {u} -{}}{\displaystyle {\scriptstyle S}} {\displaystyle {}\,p\,d\mathbf {S} }{\displaystyle \displaystyle {}+\iiint _{\scriptstyle V}\rho \mathbf {f} _{\text{body}}\,dV+\mathbf {F} _{\text{surf}}}

So, seeing as how this is basically a lot of repetition, as I have found before, it is 'dimensional.' I mean like cubed and squred, that is what you can denote those 'funny engine system' symbols as, okay?

Now, we want to find the value on the left before the equals sign. That would be [time] * [velocity cubed] [p] * [u] * [distance] * [volume]. This in other words is how much velocity or distance you get for how much volume of petrol, yes?

Now, to find that out, you need to find [time] minus [volume] = [velocity] cubed = [distance]. You do not need to know anything else, of course.

[Brett Nortje]

This is where we find the stress on each point of the moving engine, or, moving parts, in other disciplines. this motion is based on finding how fast the engine can go, obviously, and, how long it can go at that speed for.

So, acceleration would be where to observe that all of those equations are equal to [distance] times by [velocity] divided by [distance] times [time]. or, [v^xyz] + [v^ijk].

Put simpler, the acceleration between points would equal [distance] divided by [time], with the stress on the points being equal to [velocity] or the answer of the last one divided by [mass] - This would be [distance] / [time] = [energy] needs to be less than [mass], as, [mass] is stored energy.

[Brett Nortje]

I have been looking at the fatigue rules, and, found miner's rule;

Where we could say that to find [k] which I think means, basically, kilograms of stuff you can put onto the thing before it gets 'fatigued,' you would need to find [n] divided by [n], as everything else equals one or is repeated to a degree that cancels them out, yes? This means that you only need to say little [n] divided by big [n] to find the fatigue of the system, of course. This means that we need to merely take the material mass divided by the load mass, of course.

Now, I want to make a rule!

If you were to observe that each time you lay something onto something else, the last weight will negate some of the stress of the new load under a certain weight, like multiple feathers being loaded onto a camel's back, for example, then we could say that any mass that does not override the mass allowance that is negligible or overlooked by the mass of the last thing will lead to a 'fatigue acceleration' that we can overlook, of course.

Then, we could say that all fatigue is 'constant unless devalued or depleted.' This would mean that with us loading feathers onto the camel's back we could basically load them on until we load them off, yes?

So, it brings me to the material itself. The material of the mass bearing structure is [s] and the volume of it is [v]. This brings up the mass bearing allowance for the structure [s], if you were to multiply them together. Then, there is the threshold of minimum mass that can be added and not influence the structure, which, to my reckoning, would be under the weight of each elementary atom of the material.

[Brett Nortje]

It is easier to do the maths of the formula if you understand what you are trying to do.

When you see a [x] over [i], it is not enough to just know the formula as it is. Solving it will show that you understand the formula, but, do you understand what you are doing? If you understand what you are doing, it is much easier!

This is why I stress every point I make. If you understand what an engine or building mechanic is - that is it there to solve a problem that will help the use in some way - and what it is supposed to do, which you can gather from the name of the problem you are faced with, then you will make a better engineer, no doubt about that.

[Brett Nortje]

This is about finding constant values, or, values that are used a s a base or foundation for the sum you are doing. This would be like an engines measurements that do not change, or, a typical brick weight that you need to know about or it's size. Basically, this is found by this formula;

This, as you can see, has a lot of big "E" signs, which means add and subtract, okay? This will be the added values of the symbols at the bottom and the top - it is like a big plus sign, don't be scared.

So, basically is is narrowed down to [1 * a * 2n ^ -s] * [1 * b * 2n ^ -s] = 1 * [volume = prime or n * (ab) ^ volume] prime ^ -s, yes? So, seeing as how we need only find one value on either side of the equals sign, we could say that [volume] = [prime or n] and [n] = {[ab] * [6n] - [3n^-8s]} = {[ab] * [10n] ^ [-8s]}.

This means we need to take the speed for the engine or device, times eight, and, square root it to the ten times prime, which is equal to [non prime] or [prime times ten] * [ab].

So, we would say that [ab] times by [10 * prime] * [speed] = acceleration capacity, and [volume] * [ab] equals maximum speed.